How many moles of lithium are needed to produce 0.60 mol of Li3N when the reaction is carried out in the presence of excess nitrogen?
6 Li + N2 = 2 Li3N
the ratio between Li and Li3N is 6 : 2
moles Li required = 0.60 x 6/2=1.8
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6 Li + N2 = 2 Li3N
the ratio between Li and Li3N is 6 : 2
moles Li required = 0.60 x 6/2=1.8