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Gas law problems help please?
A sample of gas occupies 506.0 mL at 24 degrees C and 98.9 kPa preseure. Calculate its new volume at standared temparture & pressure.
A gas has a density of 3.124 g/L @STP . Find its density at 721 mm Hg pressure and 23 degrees C
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The ideal gas law says:
PV = nRT (where T is in Kelvin)
or: n = PV/RT is a constant for certain amount of gas. Hence:
P1*V1/RT1 = P2*V2/RT2
The new volume at standared temparture & pressure is:
V1 = (P2/P1)*V2*(T1/T2) = (98.9/101.3)*506.0*(273.2/297.2) = 454 (mL)
Density: n/V = P/RT from the ideal gas law. or:
Density1 = n/V1 = P1/RT1
Density2 = n/V2 = P2/RT2
Density2/Density1 = (P2/P1)*(T1/T2)
Therefore the required answer is:
Density2 = Density1*(P2/P1)*(T1/T2)
= (3.124 g/L)*(721/760)*(273/296) = 2.73 g/L