Thirty-three pints of acid solution contain 3 pints of pure acid.Find the number of points of pure acid that must be added to the 33 pints so that the resulting solution in 25% pure acid.
**Please show me ALL of your work, so I can understand it.
**I'm not cheating on my homework, this is just a similar problem to the one I was assigned. Please Help!!
Copyright © 2024 EBIN.TIPS - All rights reserved.
Answers & Comments
Verified answer
Let,
pure acod added = x pints
SO,
(33+x)*25/100 = 3+x,
OR,
33*25 + 25x = 300 +100x,
OR,
25x -100x = 300 -33*25 = 300 - 825,
OR,
-75x = -525,
OR,
x = 525/75 = 7 pints >============================< ANSWER
Percent of pure acid in original solution:
3 pints/33 pints = 0.09 = 9%
25% = 0.25
x = total number of pints of acid for a 25% solution
x/33 = 0.25
x = 0.25(33)
x = 8.25 total number of pints of acid for a 25% solution
8.25 - 3.00 = 5.25 number of pints added for a 25% solution
3+x = 0.25(x+33)
3+x = 0.25x+8.25
0.75x = 5.25
x = 7 pints of pure acid