3b² + 5b - 2
try guessing at the factors first. If that doesn't work, use quadratic equation.
factors of 3 are 3x1. Of 2 are 2x1
c term is negative, which means the two factors are one +, one -
(3x 2)(x 1) does this work. maybe
(3x + 2)(x - 1) no
(3x 1)(x 2) how about this one
(3x - 1)(x + 2) ok
.
3b^2+5b-2
=(3b-1)(b+2)
umm theres only one step to this question... if you cant do it in your head try learning the box method its the easiest although there are others...
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3b² + 5b - 2
try guessing at the factors first. If that doesn't work, use quadratic equation.
3b² + 5b - 2
factors of 3 are 3x1. Of 2 are 2x1
c term is negative, which means the two factors are one +, one -
(3x 2)(x 1) does this work. maybe
(3x + 2)(x - 1) no
(3x 1)(x 2) how about this one
(3x - 1)(x + 2) ok
.
3b^2+5b-2
=(3b-1)(b+2)
umm theres only one step to this question... if you cant do it in your head try learning the box method its the easiest although there are others...