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Hi A.A.,

I am french (Boulogne sur mer 62200 - FRANCE)

. . . 2 SO2 . . . + . . . O2 . . . -----> . . . 2 SO3

. . .2 moles . . . . . 1 mole

M(SO2) = M(S) + 2M(O)

M(SO2) = 32 + (2 x 16)

M(SO2) = 64 g/mole

n(SO2) = m(SO2) / M(SO2)

n(SO2) = 8 / 64

n(SO2) = 0,125 mole of SO2

For 0,125 mole of SO2, we have 9,85 kJ

. . . then :

For 2 moles of SO2, we have : ΔH = 9,85 x 2 / 0,125 = 157,6 kJ

I hope to have answered your question.

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