Verified answer

OK, let's solve the second equation for x. We get x = -2 - 5y.

Let's plug that into the first equation: 3 (-2 - 5y) + 4y = -5.

This is equal to -6 -15y +4y = -5.

Solving for y, we get -11y=1, or, y = -1/11.

Substituting this value into the first equation, we get that x = -17/11.

Hope that helps!

ok so what you do is: 3x + 4y = -5 x + 5y = -a million you multiply this line by potential of -3 to do away with x once you are attempting this you get: 3x + 4y = -5 -3x - 15y = 3 now the x's cancel out and we are left with: 4y = -5 -15y = 3 and we do the calculations ( ie. 4-15=-11 and -5+3=-2) and then we get: -11y = -2 divide during by potential of -11 y = -2/-11 considering that they're the two minuses it cancels out Givving us the respond of: y = 2/11. :D

This is a system of equations. An easier way to do this one would be by linear substitution (not elimination).

Lets start by subtracting 5x form equatin 2

x + 5y = -2

- 5y -5y

Which becomes >> x = -2 - 5y

Now we can take the value of x given from this subtraction and add it in to the upper equation.

3x + 4y = -5

Becomes >> 3(-2 - 5y) + 4y = -5

Distribute and Simplify:

-6 - 15y + 4y = -5

Becomes >> -6 - 11y = -5

Becomes >> -11y = 1

Becomes >> y = - ( 1 / 11 )

NOw we plug y into either equation (the bottom seems simpler)

x + 5y = -2

Becomes >> x + 5(-1 / 11) = -2

Becomes >> x + (-5 /11) = -2

Becomes >> x = -2 + (5/11)

Becomes >> x = (-17/11)

So your solution is

x = -17 / 11

y = -1 / 11

or

( -17/11, -1/11)

I used substitution:

x + 5y= -2 subtract 5y

x= -2- 5y Plug x into the other equation

3(-2-5y) +4y= -5

-6 -15y +4y= -5

-6 -11y= -5 add 6

-11y= 1 divide by -11

y=-1/11 Plug y into the other equation

x+5(-1/11)=-2

x-5/11=-2 add 5/11

X= -1 6/11 or -17/11

Check:

-17/11+5(-1/11)=-2

-17/11-5/11=-2

Use substitution. Solve the bottom equation for x:

x=-2-5y

Now, plug this x into the top equation and solve for y:

3(-2-5y)+4y=-5

-6-15y+4y=-5

-11y=1

y=-1/11

x is then -5(-1/11)-2 which is 5/11 - 2 or -17/11

Mult eqtn2 by 3 to get x values the same

3x + 15y=-6

subtract eqtn 1 rom new eqtn 2

11y= 11 (6--5)

y=1

sub into 1

3x +4=-5

3x=-9

x=-3

3x + 4y = -5

3x + 15y = -6

11y = -1

y = -1/11

x = -2 + 5/11

= -17/11

3x + 4y = -5

x + 5y = -2

3x + 4y = -5

(-3)x + (-3)5y = (-3)-2

3x + 4y = -5

-3x - 15y = 6

11y = 11

11/11 = 1

y = 1

x + 5(1) = -2

x + 6 = -2

x = -8

3x+4y=-5)5

x+5y=-2)-4

15x+20y=-25

-4x+-20y=8

11x=-17

So?

-11/17????