sin^2x - 1 / cos(-x)
thank you!!
= cos^2x/cos(-x)
= cos^2x/cosx = cosx
NOTE: Not -cosx as above...
1 - sin^2x = cos^2x, and cos(-x) = cos(x) so you have -cos^2x/cosx = -cosx
Copyright © 2024 EBIN.TIPS - All rights reserved.
Answers & Comments
Verified answer
sin^2x - 1 / cos(-x)
= cos^2x/cos(-x)
= cos^2x/cosx = cosx
NOTE: Not -cosx as above...
1 - sin^2x = cos^2x, and cos(-x) = cos(x) so you have -cos^2x/cosx = -cosx