Verified answer

Number of $35 tickets = x

Number of $55 tickets = 9,500 - x

Gate takings from $35 tickets, in dollars = 35x

Gate takings from $55 tickets, in dollars = 55(9,500 - x) = 522,500 - 55x

So 35x + 522,500 - 55x = 432,500

-20x = -90,000

x = 4,500

9,500 - x = 5,000

SOLUTION:

4,500 $35 tickets were sold.

5,000 $55 tickets were sold.

——————————————————

Check:

4,500 * 35 = 157,500

5,000 * 55 = 275,000

157,500 + 275,000 = 432,500

——————————————————

Let no. of $35 ticket be x and no. of $55 tickets will be 9500 - x , then 35x + 55(9500 - x) = 35x + 522 500 - 55x = 432 500 , 90 000= 20x , x = 4500

LET THE NUMBER OF $55 TICKETS SOLD BE X

THEN THE NUMBER OF $35 TICKETS SOLD WILL BE ( 9500 - X )

AMOUNT COLLECTED = 55X + 35 ( 9500 - X) = 432500

55X + 332500- 35X = 432500

20X = 100000

X = 5000

ANSWER 5000 ($55 ) TICKETS AND 4500 ($35) TICKETS

CHECK

5000 x 55 = 275000

4500 x 35 = 157500

add = 432500 $

i think more info is needed to solve this.

with the facts given there can will be multiple answers.

Edit: nope.. the answer can be found... hang on..

ok.. here is the answer

35$ ticket = x

55$ ticket = y

x + y = 9500

35x + 55y = 432500

so

x= 9500 - y

35 (9500 - y) + 55y = 432500

332500 - 35y + 55y = 432500

simplified

20y = 100000

y= 5000

5000 55$ tickets were sold

so

4500 35$ tickets were sold

35x+(9500-x)55=432500

522500-20x=432500

x=90000/20=4500

9500-x=5000

ans. Is 4500 $35tickets & 5000 $55 tickets