a parachutist of a mass of 75 kg jumps out of an airplane. just before he opens his chute, the force of the air resistance in 600N.
a)what is the weight of the parachutist?
b)what is the net force acting on the parachutist?
c)what is his acceleration?
d)how large would the air resistance have to be in order for the parachutist to reach his terminal velocity?
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Verified answer
a) W = mg = 75*9.81 = 735.75 N
b) Fnet = W - Fd = 735.75 - 700 = 35.75 N
c) a = Fnet / m = 35.75/75 = 0.477 m/s²
d) 735.75 N