I need help, someone please give me the answer D:
Write the equation of a line that has a slope of 1/2 and passes through the origin...
well, the "origin" is just the very center of a graph, point (0,0)
so written in slope-intercept form (y=mx+b)
m=slope, b = y-intercept
your equation is:
y = (1/2)x + 0
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well, the "origin" is just the very center of a graph, point (0,0)
so written in slope-intercept form (y=mx+b)
m=slope, b = y-intercept
your equation is:
y = (1/2)x + 0