2x + y = 1
x - y = 3
3x = 4
x = 4/3
y = -5/3
If 2X+Y=1,
Y=1-2X
Subtitute Y=1-2X into equation X-Y=3,
X-(1-2X)=3
X-1+2X=3
3X=4
X=4/3
When X =4/3, sub. into equation 2X+Y=1
2(4/3)+Y=1
Y= -5/3
Thus, X=4/3, Y= -5/3
x=4/3
y=-5/3
2x+y=1.............add the two equations together
x-y=3
to get
3x = 4.....divide by 3
substitute 4/3 INSTEAD of x in either of the ORIGINAL equations
2(4/3) +y = 1
y = 1-8/3
2x+y=1
Add the eqns we get : 3x + 0y = 4
so x = 4/3
putting in eqn no 2 we get
4/3 - y =3
y = 4/3 -3 = - 5/3
so solution is x = 4/3 , y = - 5/3.........................answer
2x+y=1,
x-y=3,
-------------
x=y+3,
2(y+3)+y=1,
2y+6+y=1,
3y+6=1,
3y=1-6,
3y=-5,
y=-5/3,
------------------
x-(-5/3)=3,
x+5/3=3,
x=3-5/3,
x=9/3-5/3,
x=4/3.
Answer: x=4/3, y=-5/3. (4/3, -5/3).
Give me best answer.
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Verified answer
2x + y = 1
x - y = 3
3x = 4
x = 4/3
y = -5/3
If 2X+Y=1,
Y=1-2X
Subtitute Y=1-2X into equation X-Y=3,
X-(1-2X)=3
X-1+2X=3
3X=4
X=4/3
When X =4/3, sub. into equation 2X+Y=1
2(4/3)+Y=1
Y= -5/3
Thus, X=4/3, Y= -5/3
x=4/3
y=-5/3
2x+y=1.............add the two equations together
x-y=3
to get
3x = 4.....divide by 3
x = 4/3
substitute 4/3 INSTEAD of x in either of the ORIGINAL equations
2x + y = 1
2(4/3) +y = 1
y = 1-8/3
y = -5/3
2x+y=1
x-y=3
Add the eqns we get : 3x + 0y = 4
so x = 4/3
putting in eqn no 2 we get
4/3 - y =3
y = 4/3 -3 = - 5/3
so solution is x = 4/3 , y = - 5/3.........................answer
2x+y=1,
x-y=3,
-------------
x=y+3,
2(y+3)+y=1,
2y+6+y=1,
3y+6=1,
3y=1-6,
3y=-5,
y=-5/3,
------------------
x-(-5/3)=3,
x+5/3=3,
x=3-5/3,
x=9/3-5/3,
x=4/3.
Answer: x=4/3, y=-5/3. (4/3, -5/3).
Give me best answer.