The angle of view for a 300 mm telephoto lens is 8 degrees. At 1,250 ft, what is the approximate width of the field of view? Use an arc length to approximate the chord length to the nearest foot.

Given measurements: 2.5 degrees = 1000mm, 8 degrees = 300mm, 23 degrees=105mm, 47 degrees=50mm, 75 degrees=28mm, 180 degrees=Fisheye.

We tried all things? How do you go about getting the answer to this? (the ans is 175 ft).

Bryce, thank you for answering. However, we are at the beginning of the book, in which we are not using trig functions yet. How did you derive at Tan 4 degrees?