An aqueous solution is to be prepared that will be 7.1% by mass ammonium?
nitrate. What mass of NH4NO3 and what mass of water will be needed to prepare 1.25 kg of the solution?
How do you go about working this out?
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By definition a 7.1% m/m solution of NH4NO3 means 7.1g NH4NO3 in 100g solution . By difference that would mean 7.1g NH4NO3 in 92.9g water.
You want to make 1.25kg = 1,250g of solution:
Mass of NH4NO3 = 7.1/100*1250 = 88.75g NH4NO3
Mass of water = 1250-88.75 = 1,161.25g H2O