Verified answer

Assume that there are no losses due to wind resistance.

The horizontal speed is constant (if there are no losses).

The vertical speed can be found from

v^2 = u^2 + 2as

u = 0

a = g = 9.8m/s

s = 3160 m

v = sqrt(0 + 2*9.8*3160)

= 248.9 m/s

The package hits the ground with a speed of 58.1 m/s horizontally and 248.9 m/s vertically. These two vectors can be drawn as the base and rise of a right-angle triangle. The net speed is the hypotenuse of the triangle:

net speed = sqrt(58.1^2 + 248.9^2) = 255.6 m/s (answer)

(You can also work out the angle of impact = tan^-1(58.1/248.9) = 13.1 deg)

H=Vy²/(2g)

3160=Vy²/(2×9.8)

Vy≈249 m/s

Vx=58.1 m/s

∴V=√(Vy²+Vx²)=√(249²+58.1²)≈254 m/s

it wont strike the ground at all