Does anyone know the answer to this chemistry question?
"Mass, in grams, of 6.76x10^-3 mol of CdS" I don't know how to do it. If someone could give me the answer and how they arrived at it, that would be great.
the answer is 173.23g of CdS. y get that by taking 6.76/6.02 = 1.2 moles. so then u find the Gram Forum. Mass of CdS witch = 144.41 and times it by the # of moles u have 144.41x1.2=173.23g of CdS
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the answer is 173.23g of CdS. y get that by taking 6.76/6.02 = 1.2 moles. so then u find the Gram Forum. Mass of CdS witch = 144.41 and times it by the # of moles u have 144.41x1.2=173.23g of CdS
First of all, you need the molar mass of CdS
Use your periodic table, and just add them together
You'll get 144.47 g/mol
So, you just set up a stoich problem: 6.76x10^-3 mol (144.47 g/mol) = number of grams
therefore, there are 0.9766 g in that many moles of CdS
The answer to this one is pretty simple actually:
(6.76 x 10^-3 mol CdS) x (144.477 g/mol CdS) = 0.9766 g CdS
The number 144.477 comes from the combined molar masses of Cadmium and Sulfur. Let me know if you need any more explanation