Capacitor question(physics)?
A 10.0 uF capacitor is charged to a potential of 50.0 V and then discharged through a 170 Ohms resistor.
A) How long does it take the capacitor to lose half of its charge? (in ms)
B) How long does it take the capacitor to lose half of its stored energy? (in ms)
Correct answer for 10 points. Thanks!
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Answers & Comments
Verified answer
A
Q/ Qo = e ^ [-t/ (RC)]
0.5 = e ^ [-t/ (RC)]
0.5 = e ^ [-t/ (10*170e-6]
0.5 = e ^ (-588.2 t)
t = 5 log 2 / 2941 = 0.0012 s = 1.2 ms
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B
Initial Energy stored = 0.5 * Qo²/ C
Final energy stored = ½ {0.5 * Qo²/ C) = 0.5 Q ²/C
½ Qo² = Q ²
Q/ Qo = 0.707 = e ^ (-588.2 t)
t = 0.000589467 = 0.59 ms
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