1.y=-3(x-4)^2-2
y=-4/7x+4
And
2.x+y=0
y=(x-4)^2-6
Are you trying to find the x and y?
I would first set them equal to each other.
-3(x-4)^2-2= -4/7x+4
then add 2 to both sides.
-3(x-4)^2 = -4/7x+6
and then so on, so forth from that.
For the second one, I would do the same.
except you would have to solve the first one for y
y=-x
then set them equal to each other.
I hope that helped some..
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Answers & Comments
Verified answer
Are you trying to find the x and y?
I would first set them equal to each other.
-3(x-4)^2-2= -4/7x+4
then add 2 to both sides.
-3(x-4)^2 = -4/7x+6
and then so on, so forth from that.
For the second one, I would do the same.
except you would have to solve the first one for y
y=-x
then set them equal to each other.
I hope that helped some..