Find a number X such that the line containing the points (X,-5) and (-6,8) is perpendicular to the line containing the points (4,7) and (1,11)
(X)=
Please explain the process for finding x.
Two perpendicular lines' slopes are the additive and multiplicative inverse of one another; for instance,
2 => -1/2
First, determine the slope of the line whose coordinates you know.
y2-y1/x2-x1 = 11 - 7 / 1 - 4
= 4 / -3
If the slope of the other line is perpendicular, then we find the additive and multiplicative inverse:
4 / -3 ======> -3 / 4 =========> 3 / 4
so, the slope of the line whose x-coordinate we're looking for is 3 / 4.
Slope formula again:
y2-y1/x2-x1 = 13 / -6 - x = 3 / 4
13 / (-6 - x) = 3 / 4
13 = -18/4 - 3/4x
70/4 = -3/4x
x = -70/3
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Verified answer
Two perpendicular lines' slopes are the additive and multiplicative inverse of one another; for instance,
2 => -1/2
First, determine the slope of the line whose coordinates you know.
y2-y1/x2-x1 = 11 - 7 / 1 - 4
= 4 / -3
If the slope of the other line is perpendicular, then we find the additive and multiplicative inverse:
4 / -3 ======> -3 / 4 =========> 3 / 4
so, the slope of the line whose x-coordinate we're looking for is 3 / 4.
Slope formula again:
y2-y1/x2-x1 = 13 / -6 - x = 3 / 4
13 / (-6 - x) = 3 / 4
13 = -18/4 - 3/4x
70/4 = -3/4x
x = -70/3