Does anyone know how to solve the following? xe^(2x)+1=3 The answer is supposed to be 0.601084. Thanks!?
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Does anyone know how to solve the following? xe^(2x)+1=3 The answer is supposed to be x=0.601084. I just don't know how to get to the answer, so steps would be much appreciated. Thanks!
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Because you have an x term in front, it can't be solved algebraically. You would need to use the Lambert W function (also called the omega function or the product log function) to solve.
xe^(2x) + 1 = 3
xe^(2x) = 2
x = W(4) / 2
x ≈ 1.20216787 / 2
x ≈ 0.60108393...