Chemistry Questions - 10 pts best answer!?
Which of the following elements is most likely to display sp^3d hybridization?
oxygen, nitrogen, phosphorus, carbon, boron
Assume that all the S - F bonds in S F (subscript 5) -1 are identical. The hybridization of the sulfur atomic orbitals which most likely account for this identity is:
sp sp^2 sp^3 sp^3d sp^3d^2
If 12 g water at 35.0 degree celsius water is added to 150.0 g water at 22.0 degree celsius water, what is the final temp of the resulting mixture?
22.1 degrees, 23.0 degrees, 25.2 degrees
I've tried these questions, but I can't figure them out. Please help if you can, thank you.
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Phosphorus. Its normal valence electron configuration is s2 p3, so these five electrons could be promoted to an sp3d hybridization. None of the other elements listed have empty d orbitals that could participate in the hybridization.
sp3d2. The SF5 (-1) anion has 42 valence electrons, so there is a lone pair on the central sulfur atom. This means you need room for 6 orbitals (5 for the S-F bonds and one for the lone pair), and this is the only hybridization that allows that.
23.0 degrees. If you take a weighted average, [(12g x 35.0) + (150g x 22.0)] / (12g + 150g) = 22.96.